Sort of. Yes, P:HHHH = P:THTH = P:TTTT, But P:HHHH < P:THTH [i]or[/i] TTTT. Yes, any specific combination of four Warkock items is equally likely, but the odds of four of the same Warkock item in a row is significantly lower than the odds of *not* four of the same Warkock item in a row, because the set of [lists of four Warkock items that are not all the same] contains more items than the set [lists of four Warlock items that are all the same].
EDIT: to put it another way, the probability of any specific set of four items is 1/1,296, but the probability of any set of four items that are all the same is 6/1,296 (because there are 6 sets of items meeting that criteria, each of which have a 1/1,296 chance of occurring), and the probability of any set of four items that aren't all the same is 1,290/1296.
Your role as a moderator enables you immediately ban this user from messaging (bypassing the report queue) if you select a punishment.
7 Day Ban
7 Day Ban
30 Day Ban
Permanent Ban
This site uses cookies to provide you with the best possible user experience. By clicking 'Accept', you agree to the policies documented at Cookie Policy and Privacy Policy.
Accept
This site uses cookies to provide you with the best possible user experience. By continuing to use this site, you agree to the policies documented at Cookie Policy and Privacy Policy.
close
Our policies have recently changed. By clicking 'Accept', you agree to the updated policies documented at Cookie Policy and Privacy Policy.
Accept
Our policies have recently changed. By continuing to use this site, you agree to the updated policies documented at Cookie Policy and Privacy Policy.