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Edited by Blonic :
3/6/2014 12:33:43 AM
5
Quick Calculus help. (QUESTION HAS BEEN ANSWERED)
Just wondering, could anyone quickly demonstrate how you solve this problem?
Find the derivative of y in respect to theta (I will call it T).
y=ln(T-8)
I do know you split up ln so that y = (lnT)/(ln8)
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Edited by A Kinky Milkman: 3/6/2014 12:31:57 AMthe derivative of a natural logarithm is (1/x) and usage of the chain rule. T-8 gives us 1 when derived, so there is no need to include it in the final answer. The derivative here is (dy/dT) = (1/(T-8))
