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Edited by Blonic :
3/6/2014 12:33:43 AM
5
Quick Calculus help. (QUESTION HAS BEEN ANSWERED)
Just wondering, could anyone quickly demonstrate how you solve this problem?
Find the derivative of y in respect to theta (I will call it T).
y=ln(T-8)
I do know you split up ln so that y = (lnT)/(ln8)
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3 RepliesCalculus tutor here. The standard form of a natural log derivative is ln(x) -> 1/x. In this case, we have ln(T-8), so we'll need to use the chain rule. Our outer function is ln(inner), our inner function is T-8, the derivative of the outer function is 1/(inner), the derivative of the inner function is just 1, so putting it all together we end up with 1/(T-8).
