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Edited by Blonic :
3/6/2014 12:33:43 AM
5
Quick Calculus help. (QUESTION HAS BEEN ANSWERED)
Just wondering, could anyone quickly demonstrate how you solve this problem?
Find the derivative of y in respect to theta (I will call it T).
y=ln(T-8)
I do know you split up ln so that y = (lnT)/(ln8)
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Edited by Mourner: 3/6/2014 12:27:10 AM[quote]Just wondering, could anyone quickly demonstrate how you solve this problem? Find the derivative of y in respect to theta (I will call it T). y=ln(T-8)[/quote] Uhh.. put e^ln(T-8)? Lol idk, I know that the e and ln cancel out.
