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Edited by Ronin: 5/11/2018 2:28:22 PM
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PSA: 2=1

Want to know how? Let a=b. Multiply both sides by a. Now we have a^2=ab Subtract b^2 from both sides. Now we have a^2-b^2=ab-b^2 Factor. (a+b)(a-b)=b(a-b) Divide by (a-b). a+b=b But a=b, so b+b=b Simplify 2b=b Divide by b 2=1 You’re welcome. Edit: Congrats to LahDsai to finding the error. Yes, the proof technically divides by zero. Not sarcastic at all, nice job. Took me a little bit of my own time to find the error.

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  • Edited by SuperJohnJohn: 5/10/2018 12:24:42 AM
    the math is broken by multiplication/division by zero [quote]Let a=b. Multiply both sides by a. Now we have a^2=ab Subtract b^2 from both sides. Now we have a^2-b^2=ab-b^2 Factor. (a+b)(a-b)=b(a-b)[/quote] if a=b then a-b=0 so (a+b)*0=0 and b*0=0 Logic

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