I was having trouble simplifying an expression earlier but I just solved it now while I was posting this. However, I'm still a bit confused about the results. Here is the problem.
(x^n / x^n+1) / [x^2 * (x * x^-3)]
In the book, the solution is x^-1 but I kept getting x^-3
Here's how it's supposed to be done:
(x^n / x^n+1) / [x^2 * (x * x^-3)]
(x^n / x^n+1) / [(x^2 * x) * (x^2 * x^-3)]
(x^n / x^n+1) / [(x^2+1) * (x^2-3)]
(x^n / x^n+1) / [(x^3) * (x^-1)]
(x^n / x^n+1) / [x^3-1]
(x^n / x^n+1) / [x^2]
(x^n-n+1) / [x^2] (this is where I had trouble)
(x^1) / [x^2]
x^1-2
x^-1
I kept getting x^-3 because I used the calculator for (x^n / x^n+1) only to keep getting that it simplified to x^-1
Try 2^2 / 2^3 and you get the same result as x^-1
Try 3^4 / 3^5 and you get the same result as x^-1
If it truly were x^1 then the calculator would've returned the value for x that I gave it.
(x^-1) / [x^2]
x^-1-2
x^-3
I want to know why I kept getting that answer and why I was wrong.
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Edited by aceebro: 7/23/2015 10:26:27 AMStep two is wrong. Distribution doesn't work across multiplication, only addition. [spoiler]a(b+c)=ab+ac but a(b*c)=abc[/spoiler]I have no idea wtf textbook you're using that has that in there. EDIT: I realised that this likely isn't from a textbook, but my point stands. Wherever you saw that "how it's supposed to be done" is wrong, both with the distribution, and where they said that "x^(n-(n+1))=x^1". That doesn't even make any damn sense.